## Funny Math

Theorems that prove basic mathematics is wrong!

While trying to clean up some old files/mails, I got these hilarious mathematical proofs. I don’t remember who sent these over, but it is definitely worth filing.

```Theorem : 3=4
Proof:
Suppose:
a    +    b    =    c
This can also be written as:
4a - 3a + 4b - 3b = 4c - 3c
After reorganising:
4a + 4b - 4c = 3a + 3b - 3c
Take the constants out of the brackets:
4 * (a+b-c) = 3 * (a+b-c)
Remove the same term left and right:
4 = 3
```
```Theorem : All numbers are equal to zero.
Proof: Suppose that a=b. Then
a = b
a^2 = ab
a^2 - b^2 = ab - b^2
(a + b)(a - b) = b(a - b)
a + b = b
a = 0
```
```Theorem: 1\$(dollar) = 1c(cent).
Proof:
And another that gives you a sense of
money disappearing...
1\$ = 100c
= (10c)^2
= (0.1\$)^2
= 0.01\$
= 1c
```
```Theorem: 1 = -1 .
Proof:
1/-1  =   -1/1
sqrt[ 1/-1 ]  = sqrt[ -1/1 ]
sqrt*sqrt = sqrt[-1]*sqrt[-1]
ie 1 = -1
```
```Theorem: 4 = 5
Proof:
16 - 36 = 25 - 45
4^2 - 9*4 = 5^2 - 9*5
4^2 - 9*4 + 81/4 = 5^2 - 9*5 + 81/4
(4 - 9/2)^2 = (5 - 9/2)^2
4 - 9/2 = 5 - 9/2
4 = 5
```

Posted by: Babu on April 30, 2003 06:41 AM
2. it's sacma illogical anyone who goes to 2nd graduate knows you cant divide any number to "0"
in 1st one (a+b-c)=0
2nd one a-b=0
3rd one 100c<>10c^2 it is equal to 100c=10^2c
4rh one sqrt[ -1/1 ]=i and i^2=-1
5th(4 - 9/2)^2 = (5 - 9/2)^2
4 - 9/2 = 5 - 9/2
is like (-1)^2=1^2
in the end i mean math is rocks and this site owner sucks

Posted by: from turkey on May 1, 2003 06:19 AM
3. site owner: Who said this is serious? Get a dictionary and look up the meaning for "hilarious".

Posted by: Babu on May 1, 2003 06:47 AM
4. for the first one, 4=5, you can't divide through by an unknown variable(s)

Posted by: nontoxicluvr on June 8, 2003 04:32 PM
5. Theorem 3:

\$1 = 100 Cents,

There is a lost of units, as any mathematicians and scientist will tell you when squaring a variable which a dimension, you must square the dimension as well,

Hence at the stage of:

= (10c)^2
= (0.1\$)^2
= 0.01(\$^2),

Hence the two sides remain equal, because when it comes down to it \$1 can not equal 1c.

Posted by: Paul Skinley on January 28, 2004 06:03 PM
6. About the one on 4=3. The problem is that we are dividing both sides by zero. We could have proven that 0=0 had we assumed that any number divided by zero is zero. On the other hand, we could prove it as 4=3 if we assume that a number divided by itself is equal to 1, that is, 0/0 = 1. Or we could say that infinity tends to infinity because any number divided by 0 tends to infitity. Such proofs suggest to us that as curiosity drives our attempts to understand nature, the proof of a statement doesnt always equal truth.

Posted by: Muneer Hameer on March 28, 2004 01:53 PM
7. This type of discussion is good. It made us aware of those things that we take for granted. By the way, why we can't divide any numbers by zero? Is it because our lecturer tolds us not to do so? Think about it.

Posted by: waseelang on April 25, 2004 01:42 AM
8. I am a little confused on this because I know only enough of physics and mathematics to be confused so can sombody anser this question for me? a negative value and its deffinat intigral added together will equil 0, so why can't youreverse the action to get somthing and less then nouthing (a negative value) back? In physics it is sayed that matter and energy can be neather created nor destroyed, (except in a nuclear reaction where matter is destroyed an energy created) but I am wondering if perhaps once there was no matter and it (no matter, perhaphs energy?)could have devided forming matter andanti matter? At any rate even if it is flawed, it is interesting thinking.

Posted by: cerious highschool student on October 8, 2004 12:49 AM
9. Think about dividing in the way we learned way back in elementary school.

25/5

Take 25 apples, and split them up into groups of 5 apples each.

6/6

Take 6 pennies, and put them in a pile of 6

That is all division is. Now see how this process is applied with zero in the NUMERATOR.

0/10

Take 0 dollars and split it into 10 piles.

Of course, you can do this because you can split 0 dollars into as many piles as you like.

Now for the DENOMINATOR, you get an undefined answer.

16/0

Take 16 slices of pizza and put it in zero piles.

This is impossible. There has to be at least ONE pile. The pizza can't just disappear.

Posted by: Steven on October 17, 2004 11:21 AM
10. Sure it can, anyone can eat pizza...i could probably get some friends together and take care of 16 slices easy!

Posted by: Amnistar on October 23, 2004 01:41 AM
11. Yeah genius. And the second it hits your stomach, your friend's stomach, or any stomach for that matter, it got divided in a pile. Your arguement is nonsense. Eating something doesn't make it disappear if it did we'd all be dead.

Posted by: duh on November 1, 2004 06:29 AM